What are the real solutions to the equation |x|^2 + 2|x|-? 3 = 0 ?
I tried factoring it and got 1 and -3, but that doesn't match any of the choices. How do I find the correct answer?
asked
Sam_PrepScholar |

You're right that the equation factors out to (x-1)(x+3) if you ignore the absolute value signs. If you put -3 into the original equation, it doesn't end up equalling zero because the absolute value signs turn the -3 into a regular positive 3. 3^2 + 2(3) -3 = 0
1^2 + 2(1) -3 = 0 This means that -1 also works, because -1 and 1 have the same absolute value.
answered
Sam_PrepScholar |

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