Engineering Mechanics: Statics and Dynamics, 14th Edition

Engineering Mechanics: Statics and Dynamics, 14th Edition

Authors: Russell C. Hibbeler

ISBN-13: 978-0133915426

See our solution for Question 17P from Chapter 1 from Hibbeler's Engineering Mechanics.

Problem 17P

Chapter:
Problem:
Water has a density of 1.94 slug/ft3. What is the density expressed in SI…

Step-by-Step Solution

Step 1

We are given that the density of the water is ${\rho _w} = 1.94\;{\rm{slug/f}}{{\rm{t}}^3}$

We are asked to determine the density of water in SI units.


 
Step 2

The mass $1\;{\rm{slug}}$ is equal to $14.59\;{\rm{kg}}$ in SI units, and the length $1\;{\rm{ft}}$ is equal to $0.3048\;{\rm{m}}$.


 
Step 3

Now, convert the units.

\[\begin{array}{c} {\rho _w} = 1.94\;{\rm{slug/f}}{{\rm{t}}^3}\\ = 1.94\;\left( {\frac{{{\rm{slug}}}}{{{\rm{f}}{{\rm{t}}^{\rm{3}}}}}} \right)\left( {\frac{{14.59\;{\rm{kg}}}}{{1\;{\rm{slug}}}}} \right){\left( {\frac{{1\;{\rm{ft}}}}{{0.3048\;{\rm{m}}}}} \right)^3}\\ = 9.99 \times {10^3}\;{{{\rm{kg}}} \mathord{\left/ {\vphantom {{{\rm{kg}}} {{{\rm{m}}^3}}}} \right. } {{{\rm{m}}^3}}} \end{array}\]